HILVERSUM, Netherlands (AP) _ Australian Steven Leaney broke out of a tie with England's Lee Westwood on the 18th hole Saturday and took a two-stroke lead after three rounds of the Dutch Open.

The two started the day sharing the lead, four shots in front of the field, but neither could match their form of the first two holes. Leaney shot a 1-under-par 70 to Westwood's 72, and Leaney went in front with a 199 total.

After Westwood birdied the fourth and fifth holes Saturday, he had played 41 holes without a bogey. But his game fell apart as he dropped three shots with a double-bogey on the sixth and a bogey on the seventh.

Leaney and Westwood went to the final hole tied at 13- under. Leaney birdied the hole.

Westwood's tee shot disappeared into the thick woods which line the fairways of the Hilversumsche course and after chipping out he struck a tree with his third.

He then overshot the green with his fourth and had to hole a difficult putt to get his bogey 6.

Nick Price shot a 69 to go 11-under, and was one stroke behind Westwood.